If two communicating entities are in different hosts connected by a network，there is a risk that PDUs will not arrive in the order in which they were sent，because they may traverse(71)paths through the network.If each PDUs is given a unique number，and numbers are assigned(72)，then it is a logically simple task for the receiving entity to reorder(73)PDUs on the basis of sequence number.A problem with this scheme is that，with a(74)sequence number field，sequence number will repeat.Evidently，the maximum sequence number must be(75)than the maximum number of PDUs that could be outstanding at any time.

（1）A.same

B.different

C.single

D.Unique

（2）A.randomly

B.equally

C.uniformly

D.Sequentially

（3）A.received

B.sent

C.transmitting

D.Forwarding

（4） A.various

B.diverse

C.finite

D.infinite

（5）A.smaller

B.greater

C.less

D.More

點擊進入>>>希賽軟考題庫 網(wǎng)絡(luò)工程師歷年真題在線自測！

想要了解更多軟考考試資訊，可以關(guān)注希賽網(wǎng)軟考頻道。